MENGHITUNG VOLUME GABUNGAN
BANGUN RUANG.
Jawaban:
No.1
Diket:
D = 20 cm
D ÷ 2 = r
20 ÷ 2 = 10 cm
Tinggi = 24 cm
Tentukan:
Volume Gabungan?
Jawaban:
Vtabung + V½bola
= ( πr²t ) + ( ½ × 4/3 × πr³ )
= ( 3,14 × 10² × 24 ) + ( ½ × 4/3 × 3,14 × 10³ )
= ( 31,4 × 240 ) + ( 4/3 × 3,14 × 5 × 10 × 10 )
= 7.536 + ( 4/3 × 15,7 × 100 )
= 7.536 + ( 4/3 × 1.570 )
= 7.536 + ( 6.280 ÷ 3 )
= 7.536 + 2.093,3
= 9.629,3 cm³
No.2
Diket:
D = 21 cn
D ÷ 2 = r
21 ÷ 2 = 10,5 cm
Tinggi tabung = 15 cm
Tinggi Kerucut = 40 - 15 = 25 cm
Tentukan:
Volume Gabungan?
Jawaban:
Vtabung + Vkerucut
= ( πr²t ) + ( ⅓ × πr²t )
= ( 22/7 × 10,5² × 15 ) + ( ⅓ × 22/7 × 10,5² × 25 )
= ( 33 × 157,5 ) + ( ⅓ × 33 × 262,5 )
= 5.197,5 + ( 11 × 262,5 )
= 5.197,5 + 2.887,5
= 8.085 cm³
no. 5.
Jawab:
Volume tabung = π x r² x t
= 3,14 x 10 x 10 x 24
= 7536 cm.
no. 6.
Jawab:
Diketahui:
diameter=21cm
tinggi tabung=15cm
tinggi kerucut=40cm
Ditanya:
Voleme gabungan kedua bangun ruang tersebut?
Dijawab:
V tabung=22/7×21cm×21cm×15cm
=22×3×21×15
=66×21×15
=20.790cm³
V kerucut=1/3×22/7×21cm×21cm×40cm
=22×3×7×40
. =346cm³
V gabungan=V tabung+V kerucut
=20.790cm³+346cm³
=21.136cm³
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